A body covers the first one-third of the distance with a
velocity of 10 m/s, the second one-third with a velocity of
20 m/s and the last one-third with a velocity of 30 m/s. The
average velocity is nearly:
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2
Answer:
16.36
Explanation:
Distance = Speed×time
Hence if we take distance as X then
T1 = (X/3)/10.
T2 = (X/3)/20
T3 = (X/3)/30
Now applying the same thing for the whole course,
Velocity = Distance / time
= X/(T1+T2+T3)
Substitute the values...
= X /[ X/30 + X/60 + X/90]
Taking LCM,
= 1/[(6+3+2)/180]
= 1/(11/180)
= 180/11
Which is approximately = 16.36
Hope that helps. I tried to keep it simple.
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