Question

a body covers with uniform acceleration in a straight line, distance A and B in successive intervals of time t1 and t2. What is the acceleration of the body?​

Answer 1

Answer:

The dist. travelled is equal in all intervals .Let that be s.

Now, Average velocity=(v1+v2+v3)/3

=(s/t1+s/t2+s/t3)/3

=s(1/t1+1/t2+1/t3)/3 ….(1)

Also, Average velocity=Total dist./total time

=s/(t1+t2+t3) ...(2)

From (1)&(2)

s/(1/t1+1/t2+1/t3)/3=s/(t1+t2+t3)

s will cancel out s, and shifting 3 on right hand side we get;

1/t1+1/t2+1/t3=3(t1+t2+t3)

Hence prooved.

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Answer 2

Explanation:this is ur ans 1/t1+1/t2+1/t3=3(t1+t2+t3) has proved

hope this will help u

The dist. travelled is equal in all intervals .Let that be s.

Now, Average velocity=(v1+v2+v3)/3

=(s/t1+s/t2+s/t3)/3

=s(1/t1+1/t2+1/t3)/3 ….(1)

Also, Average velocity=Total dist./total time

=s/(t1+t2+t3) ...(2)

From (1)&(2)

s/(1/t1+1/t2+1/t3)/3=s/(t1+t2+t3)

s will cancel out s, and shifting 3 on right hand side we get;

1/t1+1/t2+1/t3=3(t1+t2+t3)

Hence prooved.

Please approve my answer if u found it helpful.