Question

A body crosses the topmost point of a vertical circle
with critical speed. What will be its centripetal
acceleration when the string is horizontal :-
(1)g (2) 29 (3) 3g (4) 6g​

Answer 1

Answer:

Explanation: find the attachment below

Answer 2

When the string is horizontal, it's centripetal  acceleration is 3g.

Option - 3

Explanation:

In order to cause the topmost point the Critical speed at the lowest point of the vertical circle will be $\sqrt{5gl}$.

$\frac{1}{2}mv_{1}^2$=  $\frac{1}{2}mv_{2}^2$+ mgl

Putting the value we will get,

⇒ $\frac{1}{2}$ m(5gl) = $\frac{1}{2}mv_{2}^2$ +mgl

⇒ $v_{2}^2$ = 3gl

The centripetal acceleration of the body that will take place in horizontal direction will be

A = $\frac{v_{2}^2}{l}$

⇒ a= 3g .

To know more:

As a car speed up when rounding a curve does its centripetal acceleration increase? Use an equation to defend your answer​

https://brainly.in/question/12574206