Physics, asked by leaderhope43, 7 months ago

A body decelerates at 0.8m/s^-2 passes a certain point with a speed of 30m/s^-1. find the velocity after 10secs and distance it covered in 10secs .​

Answers

Answered by bhagwanghotia14
0

Answer:

v = u + at

v= 30 + 0.8× 10

= 38 m/s

s= ut + 1/2 at2

s= 30*10 + 1/2 *0.8*100

= 340 m

Answered by abdullahatif132
0

Answer:

The velocity can be calculated by using 1st equation of motion i.e : Vf = Vi + at

so your answer is Vf = 22 m/s.

the distance is calculated by using 2nd equation of motion : S = Vit + 1/2 at^2

so your answer is 260 meters.

Similar questions