Question

A body displaced through a distance of 5 meter
under the action of a force 10 N, acting at right
angles to the displacement. work done will be​

Answer 1

Answer:

Given

s=10m, F=5N, W=25J

For the given problem

W=F.scosθ

⇒cosθ=

F.s

W

∴cosθ=

(5)(10)

25

∴cosθ=

2

1

⇒θ=cos

−1

(

2

1

)=60

∘