A body dropped freely from a height of 80m above
the ground, the distance travelled by it in 3rd second
will be :-
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Answer:
Let the value of coefficient of restitution be e.
Initial height of the body H=80 m
Time taken by the body to reach the ground t=
g
2H
⟹ t=
10
2×80
=4 s
Total time taken by body to stop is given by T=t(
1−e
1+e
)
∴ 6=4(
1−e
1+e
)
⟹ e=0.2
Total distance travelled by body before coming to rest is given by S=H(
1−e
2
1+e
2
)
∴ S=80(
1−0.2
2
1+0.2
2
)=86.6
Explanation:
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