Question

A body dropped freely from certain height reaches the ground in 3 seconds. the ratio of the distances travelled by it in the last 3/4 second and last but one 3/4 second is​

Answer 1

Answer:

Let the stone taken n second to reach the ground

Given, u=0,a=+g

The distance covered in nth second

9

5

×distance covered in n seconds

2

g

(2n−1)=

9

5

×

2

g

n

2

⇒18n−9=5n

2

⇒5n

2

−18n+9=0

so, n=3s or 0.6s

But 0.6s time is practically not possible, hence t=3s

Explanation:

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