Question

A body dropped freely under gravity reaches the ground in 4s. find: a) velocity with which it strikes the ground. b) height from which it is thrown (g = 9.8 m s -2)

Answer 1

Answer:

u=0,  g=9.8, t=4

v=u+at

v= 39.2 m/s(velocity with which it strikes the ground)

v^2 +u^2 = 2as

1536.64 + 0 = 2 X 9.8 X s

s = 1536.64/19.6

s = 78.4 m

Explanation: