Question

A body dropped from a height h at time t = 0 reaches the ground at time to. It would have reached a
height h/2 at time t =
a)
b) to
to
d) none of these
3
Glas​

Answer 1

Answer:

Assuming the body was dropped without any initial velocity:

u = 0

t = 2 seconds

s = -h (taking downward direction to be negative)

a = -g

Using equation of motions,

s = ut + ½a(t²)

=> -h = 0*2 + ½*(-g)*2*2

=> h = 2g …(1)

Now, new distance, s' = -h/2 = -2g/2 = -g

Let time taken for covering this new distance be t'

s = ut + ½at²

=> -g = 0*2 + ½*(-g)*(t')²

=> 2 = (t')²

=> t' = √2 seconds