Question

A body dropped from a height h onto the floor makes elastic collision with the floor. The frequency of oscillation of its periodic motion is

Answer 1

Bouncing a steady object for an object, such as floor coefficient of redistribution, e = h'h - √e = h'h

⇒⇒ Height on which it h = = e2hh '= e2h bounces

Similarly, after rebounds to nth time, the height at which it rises '= e2nhh' = e2nh

E = Velocity of velocity / velocity of the perspective

Therefore, in this case the ground is in comfort, therefore,

E = V / U only

Each time it bumps to the final speed, then it becomes initial, thus increasing the power of 'E'.

N to collision: Final velocity (v) = (e ^ n) (initial velocity)

Initial velocity = (2gh) ^ 1/2

So, (v) = (e ^ n) ((2gh) ^ 1/2

Thus, because it is a similar speed,

2gH = V ^ 2

2gH = (E ^ 2n) 2gh

Thus, H = (E ^ 2n) H