Question

a body dropped from a height reaches the ground in 4 sec then the time taken to travel half of the distance after starting is​

Answer 1

Answer:

2 seconds

Explanation:

time taken to travel half distance = 4/2 = 2 seconds

Answer 2

Explanation:

time taken = 4 seconds

second equation of motion

s = ut + 1/2 × at². u = 0 (initial velocity)

s = 0 × 4 + 1/2 × g × 4². g = 10m/s²

s = 16 × 5

s = 80m

distance travelled by body is 80 metres

half of distance = 40 m

therefore

40 = ut + 1/2 × at²

40 = 0 + 1/2 × 10 × t²

40 / 5 = t²

8 = t²

t = √8 s ,3 sec (approximately)