Question

a body dropped from a height travels 36% of total distance in last second of its free fall. Then the time of its free fall is

Answer 1

Let
Total Distance = 1 m
Time of flight = T 

Then,
Distance travelled in time T - 1 = 0.64 m

For total flight
S = ut + 0.5at²
1 = 0 + 0.5gT²
2 = gT² …………[1]

For T - 1 seconds
S = ut + 0.5at²
0.64 = 0 + 0.5g(T - 1)²
1.28 = g(T - 1)² …………[2]

Divide equation [1] by [2]
2 / (1.28) = gT² / [g (T - 1)²]
100 / 64 = (T / (T - 1))²
10 / 8 = T / (T - 1)
10T - 10 = 8T
2T = 10
T = 5 seconds

Time of its free fall is 5 seconds.

Answer 2

Answer:

@Junaidmirza thank you for your answer sir/mam