Question

a body dropped from a tower and reaches the ground in 0.6 second if g is equal to 10 metre per second square find the height of Tower​

Answer 1

Answer : 1.8 m

Explanation:

Given : T = 0.6 sec

g = 10 m/s^2

initial velocity ( u ) = 0 as the body is dropped .

Let the height of tower be H

Applying equation of motion :

→ H = uT + 1/2 g T^2

→ H = 1/2 * 10 * (0.6)^2

Height of tower = 1.8 m

Answer 2

Answer:

answer is 1.8 m dear.........

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