Question

A body dropped from a tower .It acquires a velocity of 20m\s on reaching ground . Calculate height of tower. (Take g= 10 m\s^2).

Answer 1

Given,

Initial Velocity (u) = 0 m/s

Final Velocity (v) = 20 m/s

Acceleration due to Gravity = 10 m/s^2

As we know that,

v^2 - u^2 = 2gh

=> (20)^2 - 0^2 =2 x 10 x h

=> 400 - 0 = 20 h

=> h = 400/20

=> h = 20 m

Hence, the Height of tower = h = 20 m

Answer 2

Answer:

the ans is 20 m/s

Explanation:

h = 20m

g = 10

t = underroot 2gh

  = 2X10X20

  = root 400

  = 20 m/s