Question

A body, dropped from a tower with zero velocity, reaches the ground in 4 sec. The

height of the tower is..........​

Answer 1

Answer:

answer is in the pic

Explanation:

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Answer 2

Answer:

78.4 m

Explanation:

Since the body is dropped from a height its initial velocity(u) = 0

time(t) = 4s

height(s) = ?

acceleration is due to gravity so it g = 9.8 m/s²

Now we know from the second equation of motion,

that s = ut + (1/2)at²

so putting in the values we get s = 0(4) + (1/2)×9.8×4²

Therefore, s = (1/2)×9.8×16

= 78.4 m

Therefore the height of the tower is 78.4 m