Question

A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time
of fall is
(C) 1 sec
(D)
sec
(B) 4 sec
(A) 2 sec
n the around is twice that of Q. A particle is projected downward with a speed​

Answer 1

Answer:

Explanation:

For total height

H = 0.5gT^2

For first 9H/16 Height

9H/16 = 0.5g * (T - 1)^2

Divide above two equations

16/9 = [T / (T - 1)]^2

T / (T - 1) = 4/3

3T = 4T - 4

T = 4 seconds

Time of fall is 4 seconds