Question

A body dropped from the top of a tower hits the ground after 4s .how much time does it take to cover the first half of the distance from the top of the tower

Answer 1

Explanation:

Let the height of tower be : h

Given,

initial velocity u = 0

time t = 4 second

acceleration due to gravity g = 10 ms-²

h = ut + 1/2 × at²

h = (0 × 4) + 1/2 × 10 × (4)²

h = 1/2 × 10 × 16

h = 10 × 8

h = 80 m

time taken to cover first half of distance from the tower

=

h/2 = ut + 1/2 × a × t²

80/2 = (0×t) + 1/2 × 10 × t²

40 = 5 × t²

8 = t²

t = √8

t = 2.8284 seconds