Question

A body, dropped from top of building of
height 24 m reaches ground after time
't Height of body after time 0.5t
1) 6m
2) 18 m
3) 15m
4) 12m​

Answer 1

Answer:

hope it's helpful

Explanation:

If it takes time “T” to reach the ground then,

H = 0.5gT²

T = √(2H/g)

If it takes time “t” to travel first half of the journey then,

0.5H = 0.5gt²

H = gt²

t = √(H/g)

Time taken to cover second half of the journey is = T - t

= √(2H/g) - √(H/g)

= √(H/g)×(√(2) - 1)