Question

A body dropped from tower reaches the ground in 4 s what is height

Answer 1

Answer:

given ,

t= 4 sec

g= 9.8 ms^2

h=?

with eq 3

h= half*at^2

h=9.8*8

h=78.4m

Answer 2

u=0

t=4 sec

a=9.8m/s^2

s=?

s=ut+1/2at^2

s=0+1/2*9.8*(4)^2

Distance s=78.4m