Question

a body dropped with initial velocity zero from a height h strikes the ground with velocity 3m/s when a body of same mass is thrown downward with an intial velocity of 4m/s what is its velocity when it strikes the ground?​

Answer 1

Answer:

5m/s

Explanation:

Assuming this:

For the first body- v^2=u^2 +2as would be

3^2 = 0^2 + 2(9.81)(h)

Rearranging the equation for h would give you:

h = 50/109 m

For the second body- v^2= u^2 + 2as would be

v^2= 4^2 + 2(9.81)(50/109)

v = 5 m/s

NOTE :-

** These values have been calculated by taking acceleration due to gravity as 9.81 m/s^2 **

Answer 2

Answer:

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