Question

A body drops of the tower during the last second of it motion it travels 16/25 th of the hieght of the tower calculate the hieght of the tower of g=10m/s^-2​

Answer 1

Explanation:

s=16/25

g=10

h=?

t=n=?

s= u+g/2(2n-1)

16/25=0+10/2(2n-1)

16=25(10n-5)

16=250n-125

16+125=250n

141=250n

141/250=n

0.564=n=t

h=ut+1/2gt^2

h=0+1/2*10*0.564^2

h=1.590

Answer 2

Answer:

31.25 m

Explanation:

v= √2gh (taking full height)

2gh = u^2 + 2g(16/25)h

2gh(9/25)=u^2

Now , v = u + at

√2gh = 3/5√2gh +10(1)

h = 31.25 m