Physics, asked by bhongaleprathmesh2, 1 month ago

A body executing shm complete 120 oscillation /min having amplitude of oscillation 10 cm. find the velocity and acceleration of particle. when it is at distance 5 cm from the mean position​

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Answered by RoyalRaavan786
0

Answer:

The particle starts from a distance of 1 cm from the mean position towards the positive extremity. Find the ... Epoch = α = sin-1(xo/a) = sin-1(1/5) = sin-1(0.2) = 11°32' ... If the amplitude of its oscillations is 2 cm, find the velocity. ... We have vmax = ωa .... The periodic time of a body executing S.H.M. is 2 s.

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