Question

a body exerts the pressure of 95000Pa on a surface. How does the pressure vary if it's area of contact is reduced to 1/19 of its initial one. Calculate the new pressure exerted by the body....??​

Answer 1

Answer:

Calculate the vertical height of a mercury column which exerts a pressure of 81600 Pa. (Density of mercury is 13.6gcm

−3

and g=10ms

−2

).Pressure(P)=81600Pa

Density(d)=13.6gcm

−3

=13.6×1000kgm

−3

(∴1gcm

−3

=1000kgm

−3

)

Acceleration due to gravity (g)=10ms

−2

P=hdg

⇒h=

dg

P

=

13.6×1000×10

81600

⇒h=0.6m

Therefore, vertical height of mercury column is 0.6 m.

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