Question

a body falling for 2 sec covers a distance S equal to that covered in next second . taking (g=10m/s², S =?

Answer 1

Distance travelled by the body in 2 seconds is,
s=ut+12gt2 =u×2+12×g×2×2 =2u+2g


(i)Distance travelled by the body in next second is,
s=u+g22n-1 =u+g22×3-1 =u+5g2
(ii)Since, the body covers equal distance,

so from equation (i) and (ii),
2u+2g=u+5g2
or, u=g2
Now putting the value of u in equation (i), we get,
s=2u+2g
=2×g2+2g
=3g=3×10=30 m