Question

A body falling for 2 seconds covers a
distance Sequal to that covered in next
second. Taking g = 10m/s, S​

Answer 1

Answer:

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Explanation:

Given that,

A body falling for 2 sec.

g=10 m/s

2

Using equation of motion

Distance travelled by the body in 2 sec is

s=ut+

2

1

gt

2

s=u×2+

2

1

g×2×2

s=2u+2g..... (I)

Distance travelled by the body in next second is

s=u+

2

g

(2n−1)

su+

2

g

(2×3−1)

s=u+

2

5g

.....(II)

From equation (I) and (II)

2u+2g=u+

2

5g

4u+4g=2u+5g

u=

2

10

u=5 m/s

Now, put the value of u in equation (I)

s=2×5+2×10

s=30 m

The distance s is equal to the 30 m.