Question

A body falling for 2s covers a distance S equal to that covered in next second. Taking g=10m/s^2,S=
(a)30m
(b)10m
(c)60m
(d)20m​

Answer 1

Explanation:

Distance travelled by the body in 2 seconds is,s=ut+12gt2 =u×2+12×g×2×2 =2u+2g

(i)Distance travelled by the body in next second is,s=u+g22n-1 =u+g22×3-1 =u+5g2

(ii)Since, the body covers equal distance,

so from equation (i) and (ii),

2u+2g=u+5g2

or, u=g2

Now putting the value of u in equation (i), we get,

s=2u+2g

=2×g2+2g

=3g=3×10=30 m

Answer 2

Answer:

A body falling for 2s covers a distance S equal to that covered in next second. Taking g=10m/s^2,S=(a)30m or 20m