Question

A body falling freely, under the action of
gravity passes two points 10 metres
apart vertically in 0.2 second. From what
height, above the higher point, did it start
to fall? step by step​

Answer 1

Step-by-step explanation:

AC=0+

2

1

g(t

1

+1)

2

and AB=

2

1

gt

1

2

AC−AB=30m

⟹

2

1

g[(t

1

+1)

2

−t

1

2

]=30

⟹2t

1

+1=

g

60

⟹t

1

=2.56[g=9.8]

AB=

2

1

g(t

1

)

2

=32.1m

Answer 2

I got the answer. Hope it helps you.