Question

A body falling from a vertical height of 10 m Pierce through a distance of 1m in sand.it faces an average retardation in sand equal to

Answer 1

Velocity when it hits the sand
v = sqrt(2gH)
= sqrt(2 × 9.8 × 10)
= 14 m/s

Retardation = v^2 / (2S)
= 14^2 / (2 × 1)
= 98 m/s^2

Average retardation in sand = 98 m/s^2