Question

A body falling from high minaret travels 40 m in last 2 sec of its fall to ground.height of minaret in m is

Answer 1

This problem can easily be solved with the help of equation of motion.

s = ut + 1/2 at^2
40 = 2u + 1/2.10.(2)^2
40 = 2u + 20
2u = 20

u = 10 m /s
Now,

v^2-u^2 = 2as
2.10.s=100
s = 5m

Hence the total distance traveled is 45M.

Answer 2

Hope this helps you..