Question

A body falling from rest, covers 44.1 m in the last second
of its fall. Find the time of fall and the height from which it fell.​

Answer 1

$g = 10 \: ms {}^{ - 2}$

$u = 0$

$s = 44.1 \: m$

$\huge\red{\mathbb{USING \: FORMULA}}$

$s = ut + \frac{1}{2} at {}^{2}$

$44.1 = 0 \times t + \frac{1}{2} \times 10 \times t {}^{2}$

$5t {}^{2} = 44.1$

$t = \sqrt{ \frac{44.1}{5} }$

$\huge\red{\boxed{\green{t = 2.96 \: sec}}}$

$\huge\pink{\boxed{\green{h = 44.1 \: m}}}$