Question

a body falling from rest describes distance S1,S2,S3 in the first, second and third second of its fall .then the ratio of S1:S2:S3 ??​

Answer 1

$answer$

S=ut+12gt2S=ut+12gt2, u=0u=0

S=12gt2S=12gt2

Here s is displacement.

Distance dropped in 1st1st second, S1=12g×(1)2=12g×1S1=12g×(1)2=12g×1

Distance dropped in 2nd2nd second, S2=12g×(2)2−12g×(1)2=12g×3S2=12g×(2)2−12g×(1)2=12g×3

Distance dropped in 3rd3rd second, S3=12g×(3)2−12g×(2)2=12g×5S3=12g×(3)2−12g×(2)2=12g×5

S1:S2:S3=1:3:5