Question

A body falling from rest describes distance S1,S2,S3 in the first, second and third second of its fall .Then what is the ratio of S1:S2:S3 ?​

Answer 1

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Alternate method

Wᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ,

S=ᴜᴛ+1/2ɢᴛ^2

ᴜ=0

S=1/2ɢᴛ^2

Hᴇʀᴇ s ɪs ᴅɪsᴘʟᴀᴄᴇᴍᴇɴᴛ.

Dɪsᴛᴀɴᴄᴇ ᴅʀᴏᴘᴘᴇᴅ ɪɴ 1sᴛ sᴇᴄᴏɴᴅ,

S1=1/2ɢ×(1)^2=1/2ɢ×1

Dɪsᴛᴀɴᴄᴇ ᴅʀᴏᴘᴘᴇᴅ ɪɴ 2ɴᴅ sᴇᴄᴏɴᴅ,

S2=1/2ɢ×(2)^2

=1/2ɢ×3

Dɪsᴛᴀɴᴄᴇ ᴅʀᴏᴘᴘᴇᴅ ɪɴ 3ʀᴅ sᴇᴄᴏɴᴅ,

S3=1/2ɢ×(3)^2=1/2ɢ×5

S1:S2:S3=1:3:5

Explanation:

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Answer 2

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• As per gallelio's law , ratio of a body falling from rest in the 1,2,3,4....seconds will be 1 : 3 : 5 : 7: ......