Question

A body falling from rest has a velocity ‘v’ after it falls through a distance ‘h’. The distance it has to fall down further, for its velocity to become double, is…times ‘h’

Answer 1

We have,

v² = 2gh

(V1/V2)² = h1/h2

=>( v/2v )² = h/h2

h2 = 4h

Regards

Kshitij