Question

A body falls 16m in the first second of its motion,  48m in the second, 80m in the third and so on. How long will it take to fall 4096m?​

Answer 1

Answer:

16 seconds

Step-by-step explanation:

the series for distance it fall is

16,48,80............... which is AP

let it takes N seconds to fall 4096m

therfor sum of series for N terms=4096

or (N/2)(2*16+(N-1)*32)=4096

or, 16(N^2)=4096

or, (N^2)=4096/16=256

or N=16

 

THerfor time required to fall 4096=16 seconds

Answer 2

$\underline \purple{ ANSWER :-}$

The series for distance it fall is

16,48,80............... which is AP.

Let it takes N seconds to fall 4096m

Therefore the sum of series for N terms=4096

or (N/2) (2 × 16+(N-1) × (32)=4096

or, 16(N²)=4096

or, (N²)=4096/16=256

or N=16

Therefore time required to fall 4096 = 16 seconds.