Question

a body Falls 8 metre in the first second of its motion 24 m in the second second 40 metre in the third and so on how long will it take to fall 2048 Metre?

Answer 1

Apply formulae for distance in nth seconds and solve two linear equations, you will cone across result that, body had initial velocity zero and acceleration of 16 mps^2,

now applying second law of motion, we get

2048= (0) t + 1/2(16) t^2
t^2 = 256
t= 16 sec

Answer 2

Answer:

The AP is 8, 24, 40,..., and the sum is 2048.

We have to determine n.

Here a = 8, d = 16

Since, Sn = 2048, we have

2048 = begin mathsize 12px style straight n over 2 end style [2 x 8+(n - 1)16]

2048 = n [8 + 8n - 8]

2048 = 8n2

n2 = 256 i.e. n = 16

(as n being number of terms, it can't be negative)

Hence, the body will take 16 seconds to fall 2048 metres.

hope it helps

tq............///////////

Step-by-step explanation: