Question

A body falls feom a height of 45 m from the ground. Find the time taken by the body to reach the ground. take g = 10 m s ^-2​

Answer 1

Answer:

3 sec

Explanation:

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Answer 2

s = 45m

u = 0

a = 9.8 m/s^2

using the kinematic equation ,

s = ut + 1/2 at^2

45 = (0×0) + 1/2 (9.8 × t)^2

45 = 9.8t^2/2

45 × 2 = 9.8t^2

90 = 9.8t^2

9.183 = t^2

t = 3.030457.. seconds