Question

A body falls feom a height of 45 m from the ground. Find the time taken by the body to reach the ground. take g = 10 m s ^-2​

Answer 1

Answer:

Correct Question:-

A body falls from a height of 45 m from the ground. Find the time taken by the body to reach the ground. Take g $= 10 \: m \: s {}^{ - 2}$

Given:-

u = 0 m/s

g = 10 m s$^{–2}$

s = 45 m

where u means initial velocity;

g means acceleration due to gravity

and s means distance travelled.

To find:-

Time taken by the body to reach the ground.

Solution:-

Using Newton's second equation of motion,

s = ut + 1/2gt$^{2}$, we get

$\Longrightarrow$ 45 = 0 + 1/2 × 10$^{2}$

Therefore, t$^{2}$ = 90/10 = 9

$\Longrightarrow$ t$^{2}$= 3 s

Thus, time taken by the body to reach the ground is 3 s.

Answer 2

Answer:

3s will be the correct answer hope it helps you