Question

A body falls for 4 sec from start. If the acceleration due to gravity of earth ceases to act then the velocity and distance it travels in the next 3 sec is
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Answer 1

Answer:

Velocity = 30m/s

Distance = 45m

Explanation:

For start, initial velocity=u=0

given, t=3 s

g=10m/s^2

By Newton's first equation of motion,

v=u+g*t

v=0+(10*3)

v=30m/s

By Newton's Third equation of motion,

s=(u*t )+ (1/2)*(g*t^2)

s= 0+(1/2)*10*(3^2)

s=5*9

s=45 m

Thank you

Answer 2

Answer:

147m

Explanation:

The body starts it's motion from rest

therefore u=0

the distance traveled be A when acceleration

due to earth t=5sec

FORMULA-V=U+AT

=0+9.8×5

=49m/s

when u stops acts the v of the body is 49m/s let's know in next 3 sec how much distance it will travel

S=UT+1/2GT2

49×3+1/2×0×t2

48×3

=147m

hence completed