Question

A body falls for 5 s from rest. If the acceleration due to gravity of earth ceases to act, the distance it
travels in the next 3 s is
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Answer 1

Answer:

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Explanation:

Initially the body starts its motion from rest therefore u=0. Let journey be A when a acceleration of earth is acting on the body time =5 seconds let's find v

v=u+at

  =0+9.8×5=49m/s

When acceleration stops acting the velocity of the body is 49m/s. Now the distance traveled by the body in next 3s

S = utInitially the body starts its motion from rest therefore u=0. Let journey be A when a acceleration of earth is acting on the body time =5 seconds let's find v

v=u+at

  =0+9.8×5=49m/s

When acceleration stops acting the velocity of the body is 49m/s. Now the distance traveled by the body in next 3s

S=ut+  $\frac{1}{2}$$gt^{2}$

= 49 x 3 + $\frac{1}{2}$ x 0 x $t^2$

= 49 x 3  

= 147