a body falls for 5s from rest .if the acceleration due to gravity of earth ceases to act the distance it travels in the next 3s
Answers
Answered by
19
Hey!
Time for it falls = 5s
Acceleration due to gravity = 10 m/s^2
Initial velocity (u) = 0
Final velocity (v) = ?
v= at+u
v= 10×5
v= 50 m/s
Distance travelled in next 3s without acceleration due tp gravity = Speed × Time
Distance = 50×3
Distance = 150 m
Hope it helps ...!!!
Time for it falls = 5s
Acceleration due to gravity = 10 m/s^2
Initial velocity (u) = 0
Final velocity (v) = ?
v= at+u
v= 10×5
v= 50 m/s
Distance travelled in next 3s without acceleration due tp gravity = Speed × Time
Distance = 50×3
Distance = 150 m
Hope it helps ...!!!
Answered by
8
Answer:
147m
Explanation:
Initially the body starts its motion from rest therefore u=0. Let journey be A when a acceleration of earth is acting on the body time =5 seconds let's find v
v=u+at
=0+9.8×5=49m/s
When acceleration stops acting the velocity of the body is 49m/s. Now the distance traveled by the body in next 3s
S=ut+1/2gt² =49×3
=49×3
=147m.
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