Question

A body falls freely from a height 'h' after two seconds if accelaration due to gravity is reversed the

bodygo​

Answer 1

Answer:

s=12gt2 (at body starts from rest, u=0)

s=12∗9.8∗(2)2=19.6m

In the remaining t secs, it has to cover d=125−19.6=105.4m. The time t taken for this remaining journey is -

t=d/v, where v is the speed the body has reached by the end of 2 secs, which is v=gt (since initial speed u=0)

v=9.8∗2=19.6m/s

Now we can find time t -

t=d/v=105.4/19.6=5.37secs

The total time taken is 2+5.37=7.37 sec

Step-by-step explanation:

please mark as me brainlist and follow me