A body falls freely from a height ‘h’ after two seconds if acceleration due to gravity is reversed the body
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Answered by
2
Answer:
h=21g(t1+t2)2
g2h=(t1+t2)2→(1)
2h=21gt12
t12=gh→(2)
From (1) & (2)
t12=2(t1+t2)2
t1=1.41(t1+t2)
t1=0.41t2⇒ so, t1=2.414t2
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Answered by
0
Answer:
H=21gm(t1 +t2) =2
G2h =(t1+t2) =3
Explanation:
So t1"=0.41t2 =t1. 414t2
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