A body falls freely from a height h describes 7h/16
Answers
Answered by
2
Answer:
The time taken to fall a from a height of 'h' to ground under gravity = √2h/g = t. In time (t-1) it travels h - 7h/16 = 9h/16. ∴ (t-1) = √2(9h)/16g. On taking the ratio, we get t/t-1 = √16/9 = 4/3.
Answered by
1
Answer:
A body freely falling from height h describes 7h/16 in last second of its fall . The height h is (g = 10 ms^-2)
follow this method in this type of numericals..
hope it helps you...
hope you understand....
mark as brainliest....
follow me....
Similar questions
Social Sciences,
5 months ago
Science,
5 months ago
Science,
5 months ago
Political Science,
9 months ago
Biology,
1 year ago