Physics, asked by varabhushan98, 10 months ago

A body falls freely from a height of 125m (g=10m/s^2) after 2 seconds gravity caeses to act. The time taken to reach the ground is​

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Answered by Anonymous
15

Given that, height = 125 m and time = 2 sec

We have to find the time taken by the body to reach the ground.

The body is under free fall. So, initial velocity (u) is 0 m/s.

Also, given that g = 10 m/s²

Using Newton's Second equation of Motion

s= ut + 1/2at²

s = 0(2) + 1/2 × 10 × (2)²

s = 0 + 5(4)

s = 20 m

In the first 2 seconds, the body travels a distance of 20 m.

Left distance = 125 - 20 = 105 m (displacement)

Using Newton's First equation Motion

v = u + at

v = 0 + 10(2)

v = 20 m/s

Now,

Time = Displacement/Velocity

Time = 105/20

Time = 5.25 sec

Time taken to reach the ground = (To cover a distance of 20 m) + To cover a distance of 105 m)

Time taken to reach the ground = (2 + 5.25) sec = 7.25 sec

Answered by Anonymous
0

Explanation:

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