A body falls freely from a height of 125m (g=10m/s^2) after 2 seconds gravity caeses to act. The time taken to reach the ground is
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Given that, height = 125 m and time = 2 sec
We have to find the time taken by the body to reach the ground.
The body is under free fall. So, initial velocity (u) is 0 m/s.
Also, given that g = 10 m/s²
Using Newton's Second equation of Motion
s= ut + 1/2at²
s = 0(2) + 1/2 × 10 × (2)²
s = 0 + 5(4)
s = 20 m
In the first 2 seconds, the body travels a distance of 20 m.
Left distance = 125 - 20 = 105 m (displacement)
Using Newton's First equation Motion
v = u + at
v = 0 + 10(2)
v = 20 m/s
Now,
Time = Displacement/Velocity
Time = 105/20
Time = 5.25 sec
Time taken to reach the ground = (To cover a distance of 20 m) + To cover a distance of 105 m)
Time taken to reach the ground = (2 + 5.25) sec = 7.25 sec
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