Question

A body falls freely from a tower and travels a distance of 40 m in its last two seconds. The height of
the tower is (take g = 10 m/s^2):
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Answer 1

we use the third equation h=ut+1/2gt^2

u=0 m/s

g=10 m/s^2

t=2 sec

h=?

h=ut+1/2at^2

or, h=0×2+1/2×10×2×2

or, h=0+5×4

or, h=20 m

so, the height of the tower is 20 m