A body falls freely from rest and has velocity v after it falls through height h. The s
Distance it has to fall down farther for its velocity to become double is
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I AM NOT SURE
HIEGHT = d = s [displacement]
u = 0
v = 2v
s =ut +1/2 at ²
s = 1/2 at ²
now
v = u + at
2v = at
put in older eq.
s = 1/2[2v] ²
s = 1/2 4v
s = 2v
hence
the distance = the velocity
MAYBE THIS ANSWER IS WRONG
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