A body falls freely from rest.Find
(a).its acceleration
(b).the distance it falls in 3s
(c).its speed after falling 70m
(d).the time required to reach a speed of 25m/s
(e)the time taken to fall 300m.
Please Answer me.
Answers
Answered by
50
(a). Since, the body is falling freely from the rest, it will be having the acceleration equal to the acceleration due to the Gravity.
∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².
(b). initial velocity (u) = 0
time(t) = 3 seconds.
∴ S = ut + 1/2at²
⇒ S = 0 + 1/2 × 10 × 9
∴ S = 45 m.
(c). v² - u² = 2aS
v² = 2 × 10 × 70
∴ v = √1400
∴ v = 37.41 m/s.
(d). v - u = at
∴ 25 - 0 = 10 × t
∴ t = 2.5 seconds.
(e). S = ut + 1/at²
∴ 300 = 0 + 1/2 × 10 × t²
∴ t² = 60
∴ t = 7.75 seconds.
Hope It Helps .
Answered by
22
a). Since, the body is falling freely from the rest, it will be having the acceleration equal to the acceleration due to the Gravity.
∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².
(b). initial velocity (u) = 0
time(t) = 3 seconds.
∴ S = ut + 1/2at²
⇒ S = 0 + 1/2 × 10 × 9
∴ S = 45 m.
(c). v² - u² = 2aS
v² = 2 × 10 × 70
∴ v = √1400
∴ v = 37.41 m/s.
(d). v - u = at
∴ 25 - 0 = 10 × t
∴ t = 2.5 seconds.
(e). S = ut + 1/at²
∴ 300 = 0 + 1/2 × 10 × t²
∴ t² = 60
∴ t = 7.75 seconds.
Please mark this answer as brainliest ✨✨
∴ Acceleration = g = 9.8 m/s². ≈ 10 m/s².
(b). initial velocity (u) = 0
time(t) = 3 seconds.
∴ S = ut + 1/2at²
⇒ S = 0 + 1/2 × 10 × 9
∴ S = 45 m.
(c). v² - u² = 2aS
v² = 2 × 10 × 70
∴ v = √1400
∴ v = 37.41 m/s.
(d). v - u = at
∴ 25 - 0 = 10 × t
∴ t = 2.5 seconds.
(e). S = ut + 1/at²
∴ 300 = 0 + 1/2 × 10 × t²
∴ t² = 60
∴ t = 7.75 seconds.
Please mark this answer as brainliest ✨✨
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