A body falls freely from the top of a tower and falls through 55m during last second of fall.Find height of tower
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use motion of kinematics formulae and eqn s= it+1/2 gtsq
RohanAcharya:
can u totally solve it
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OK
According to the motion of free fall of a body in the n the second of the fall to total distance fall through n seconds is as
Sn=(1/2)×g×(2n-1),S in n second=(1/2×g×n².Now taking the ratio of both is (2n-1)/n²=55m
solve u will get ans
According to the motion of free fall of a body in the n the second of the fall to total distance fall through n seconds is as
Sn=(1/2)×g×(2n-1),S in n second=(1/2×g×n².Now taking the ratio of both is (2n-1)/n²=55m
solve u will get ans
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