A body falls freely from the top of a tower.it covers 36percent of the total height in the last second,before striking the ground
the height of the tower(g=10)
a)50m. b)75m.
c)100m. d)125m.
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Let H be the height of the building and t be the time to fall through this height H.
Then H = ½ g t^2 = 5 t^2. -- (1)
In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H.
0.64 H = 5 (t-1)^2.------(2)
on doing (2) / (1)we get
0.64 = (t-1)^2/ t^2
Or 0.8 = (t-1) / t
Solving we get t= 5 second.
Using (1) we get H = 125 m
Then H = ½ g t^2 = 5 t^2. -- (1)
In (t-1) second the distance traveled is 1 - 0.36 H = 0.64 H.
0.64 H = 5 (t-1)^2.------(2)
on doing (2) / (1)we get
0.64 = (t-1)^2/ t^2
Or 0.8 = (t-1) / t
Solving we get t= 5 second.
Using (1) we get H = 125 m
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