Physics, asked by bablusharma387, 6 months ago

A body falls from a height A = 200 m. The rated
distance travelled in each 2 sec, during t=0 to t=6
second of the journey is
(a) 1:4:9
() 1:2:4
() 1:3:5
( 1:2:3 ​

Answers

Answered by mgulamsabir569
3

Explanation:

Distance in first two seconds=

1/2g(2)square

=20

Distance in first four seconds=

1/2g(4) square

=80

Distance in first six seconds=

1/2g(6)square

=180

Ratio=20:(80−20):(180−80)=20:60:100

=1:3:5

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