A body falls from a height A = 200 m. The rated
distance travelled in each 2 sec, during t=0 to t=6
second of the journey is
(a) 1:4:9
() 1:2:4
() 1:3:5
( 1:2:3
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Explanation:
Distance in first two seconds=
1/2g(2)square
=20
Distance in first four seconds=
1/2g(4) square
=80
Distance in first six seconds=
1/2g(6)square
=180
Ratio=20:(80−20):(180−80)=20:60:100
=1:3:5
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